Celsius to Fahrenheit, basic C++

[agwing]

#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;

int _tmain(int argc, _TCHAR* argv[])

{
double V,W,X,Y,Z,A,B,C,D,E;

cout << setw(50) << "Celsius to Fahrenheit Converter \n \n" << endl;// set width to 50 places
  

cout << setw(50) << " #1) Enter the temperature in degrees celsius \n \n";
      cin >> A;
	  V=(((9/5)*A)+32);
  cout << setw(50) << " #2) Enter the temperature in degrees celsius \n \n";
      cin >> B;
	  W=(9/5)*B+32;
  cout << setw(50) << " #3) Enter the temperature in degrees celsius \n \n";
      cin >> C;
	  X=(9/5)*C+32;
  cout << setw(50) << " #4) Enter the temperature in degrees celsius \n \n";
	  cin >> D;
	  Y=(9/5)*D+32;
  cout << setw(50) << " #5) Enter the temperature in degrees celsius \n \n";
      cin >> E;
	  Z=(9/5)*E+32;



cout << setw(25) << "CELSIUS" << setw(12.5) << "FAHRENHEIT" << endl;
cout << "\n \n";
	  
	  
cout << setw(25) << A << setw(12.5) << V << endl;
cout << "\n \n \n";
cout << setw(25) << B << setw(12.5) << Y << endl;
cout << "\n \n \n";
cout << setw(25) << C << setw(12.5) << X << endl;
cout << "\n \n \n";
cout << setw(25) << D << setw(12.5) << W << endl;
cout << "\n \n \n";
cout << setw(25) << E << setw(12.5) << Z << endl;

cout << "\n \n";
system ("pause");

	return 0;
}

The problem is that the end result is always +32 of the input. The *(9/5) is not factored...I don't understand why.

[Disch]

9 and 5 are both integers. Therefore the compiler will do integer division.

9 / 5 = 1

Therefore 9/5*X = 1*X = X

Other solutions are:

X*9/5 (do the multiplication first)

or

9.0/5.0 * X (do floating point division)

[agwing]

Thanks!