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Any pro can find the solution?
Write a program with a function int distinct(int *p, int n);
where the parameter pointer p is the base address of an array of size n. The function returns the number of distinct (unique) elements in the array.
E.g., suppose array x has contents {1,6,4,6,1}. Then the call distinct(x, 5) should return 3. (The three distinct elements are 1,6,4.)
where the parameter pointer p is the base address of an array of size n. The function returns the number of distinct (unique) elements in the array.
E.g., suppose array x has contents {1,6,4,6,1}. Then the call distinct(x, 5) should return 3. (The three distinct elements are 1,6,4.)
Just to hijack yet another thread :-) may I ask if there’s a method to determine which of these two options is faster (or let’s say more efficient) without testing them?
std::set<int> + size()
vs
std::unordered_set<int> + bucket_count()
std::set<int> + size()
vs
std::unordered_set<int> + bucket_count()
unordered_set should generally be faster since it uses a hash table instead of a balanced binary tree.
But you should still use size() if you want the number of elements it contains.
But you should still use size() if you want the number of elements it contains.
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