Inputting 0101 and store as 101

[Endeavour]

Is there any way to do that? For example, the user input 0101 to the program and the program stores the value as 101 in integer type.

I tried this:

int val = 0101;
cout<<val<<endl;

the output is: 65

um... when I did the same in my calculator, this phenomenon did not happen.

Please advise.

[hamsterman]

cout<< means output.. and you need input. cin >> val by default should give you the result you need. Now you got 65 because in c++ when you start integer with 0 that means base 8 (and 0x means base 16)

[Duthomhas]

When you cin >> somenumber then leading zeros are discounted.

However, in C++ code, leading zeros indicate an octal constant. Hence:

int a = 0101;
int b =  101;
cout << a << " == " << b << ": " << boolalpha << (a == b) << endl;

The constant '101' is equal to decimal 101.
The constant '0101' is equal to decimal 65.

Hope this helps.