Make a function template output it's type?

[KarlisRepsons]

Is that possible (scalably) to output the type of a function template instance from itself?

Say, if I use function<const void* const> or function<char*>, then I'd like to see "const void* const" and "char*" in output of function...

[helios]

typeid does that. Sort of. Otherwise, it's impossible.

[KarlisRepsons]

Hmm... Then it's impossible, because typeid didn't see any difference between int and const int when I tried.