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Defining class of rational numbers
I am trying to write a program that sets up a class for rational numbers. When i type in 15/-32 the output is -16/31 which is wrong.when i type 1/3+1/3 it gives me 1/3 which is wrong. when i type 3/4 / 1/2 it gives me 3/4 and when i type in 2/3*1/3 it gives me 2/3.which are all wrong so my proplem is it doesnt give me the right answers. How can I fix it? for the rest of the question pls read my second postthank you
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That's a lot of reading, and I probably missed something.
Do you have a method of (during calculations) determining which operations are executed first?
-Albatross
Do you have a method of (during calculations) determining which operations are executed first?
-Albatross
Okay, cancel what I just said.
It looks like your program just spits out the first two integers and the first operator you feed it.It sounds like you need a while loop that will look ahead two integers and two operators to determine what to do. Okay, cancel that. This is not an easy problem.
-Albatross
It looks like your program just spits out the first two integers and the first operator you feed it.
-Albatross
Last edited on
Like this?
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This is no easy problem, as I said above. Really. If you want to parse expressions, you will need a LOT more code.
If your program will only accept rational numbers in fraction form, then it's easy to explain. Store the expression to a block memory outside of your class (you'll need two classes), preferably a vector that will store integers, and have a function that will convert your operators to integers to represent those operations.
Use <ctype.h> to determine when to move to a new space in the vector.
Your program will read the first block and the third block, and set the numerator and denominator (in your first class) to those, respectively. Then, it will read the fifth block and seventh block, and store that in the second class's numerator and denominator. Then, perform the computation between them according to what is stored in the fourth block. Delete the first seven blocks of the vector, and then use push_back() to write (in this order) the denominator of the result of your computation, a division integer, and the numerator of the result of your computation.
Proceed until you get an error that the fourth block doesn't exist, at which point you're done.
Or just use Flex and Bison.
-Albatross
If your program will only accept rational numbers in fraction form, then it's easy to explain. Store the expression to a block memory outside of your class (you'll need two classes), preferably a vector that will store integers, and have a function that will convert your operators to integers to represent those operations.
Use <ctype.h> to determine when to move to a new space in the vector.
Your program will read the first block and the third block, and set the numerator and denominator (in your first class) to those, respectively. Then, it will read the fifth block and seventh block, and store that in the second class's numerator and denominator. Then, perform the computation between them according to what is stored in the fourth block. Delete the first seven blocks of the vector, and then use push_back() to write (in this order) the denominator of the result of your computation, a division integer, and the numerator of the result of your computation.
Proceed until you get an error that the fourth block doesn't exist, at which point you're done.
Or just use Flex and Bison.
-Albatross
Last edited on
Okay... I could help a bit. I will try to write as little code as possible. I will also explain how to do this using the C set of functions for reading and writing.
I'm assuming your operators are correct, that a class containing 3/2 and a class containing 2/3 when multiplied using the operator will set the first class to 6/6.
Get an extra rationalNumbers class in main(), called test2 (example). Then, you will need
---------------
You will be storing your data in this deque. Make a function that uses a while loop, named
Now, inside, you will check your string character by character. For this, you will need four strings and four integers.
Read each character until you get something that isn't an integer and isn't a whitespace, then copy everything up to that point into your first string, convert it to and integer, and store it in your first integer. Continue reading until you find something that is an integer, then copy what you read into the second string, convert it to your integral representation of your operator, store it in the second integer. Repeat, except using the third and fourth strings and ints.
Then, use push_back() for your deque to insert your integers into your deque. Repeat this and the above paragraph until you reach the end of the string you're reading from.
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From there, in main(), read the first block and the third block, and set the numerator and denominator (in your first class) to those, respectively. Then, read the fifth block and seventh block, and store that in the second class's numerator and denominator. Then, perform the computation between them according to what is stored in the fourth block (I recommend using a chain if if-else statements).
Delete the first seven blocks of the deque using pop_front(), and then use push_front() to write (in this order) the denominator of the result of your computation, a division integer, and the numerator of the result of your computation.
http://cplusplus.com/reference/stl/deque/
Keep going until your deque has exactly three elements.
-Albatross
I'm assuming your operators are correct, that a class containing 3/2 and a class containing 2/3 when multiplied using the operator will set the first class to 6/6.
Get an extra rationalNumbers class in main(), called test2 (example). Then, you will need
deque<int> data; (not vector). Also, you will need a string called input. Store the output from your cin in this.---------------
You will be storing your data in this deque. Make a function that uses a while loop, named
int read(deque<int> &inp). Inside, you will need a boolean value set to zero. You will also need three integers, and two strings. From there, initialize the second string to anything, so long as it's not a newline. while (string2 != "\n")Now, inside, you will check your string character by character. For this, you will need four strings and four integers.
Read each character until you get something that isn't an integer and isn't a whitespace, then copy everything up to that point into your first string, convert it to and integer, and store it in your first integer. Continue reading until you find something that is an integer, then copy what you read into the second string, convert it to your integral representation of your operator, store it in the second integer. Repeat, except using the third and fourth strings and ints.
Then, use push_back() for your deque to insert your integers into your deque. Repeat this and the above paragraph until you reach the end of the string you're reading from.
---------------
From there, in main(), read the first block and the third block, and set the numerator and denominator (in your first class) to those, respectively. Then, read the fifth block and seventh block, and store that in the second class's numerator and denominator. Then, perform the computation between them according to what is stored in the fourth block (I recommend using a chain if if-else statements).
Delete the first seven blocks of the deque using pop_front(), and then use push_front() to write (in this order) the denominator of the result of your computation, a division integer, and the numerator of the result of your computation.
http://cplusplus.com/reference/stl/deque/
Keep going until your deque has exactly three elements.
-Albatross
Last edited on
Your division operator should multiply numerator 1 * denominator 2 and denominator 1 * numerator 2, assuming that's what's in block 4 of your deque.
-Albatross
EDIT: Number of days in a year posts, and counting.
-Albatross
EDIT: Number of days in a year posts, and counting.
Last edited on
is this right?
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ok thank you. The interface is the classes part.
what is the implementation and the application/driver file in this example?
what is the implementation and the application/driver file in this example?
I do not understand your question. The implementation of what? And what application file?
-Albatross
-Albatross
How can I create an interface file, implementation file and an application/ driver file from this program
Do you know how to use your compiler for two files? One file?
As for the interface file, cut out (but don't delete) all your declarations from the file you have (that is, everything between the keyword class (there should be only one in your file), and the semi-colon).Paste them into a separate file that ends with
The header file, as we call them, is anything but mandatory. That file will compile just fine on its own, assuming you don't modify it from what works.
-Albatross
As for the interface file, cut out (but don't delete) all your declarations from the file you have (that is, everything between the keyword class (there should be only one in your file), and the semi-colon).Paste them into a separate file that ends with
.h. Then, use your compiler to compile both of them at the same time. Assuming your compiler is sane, you should get an executable from that.The header file, as we call them, is anything but mandatory. That file will compile just fine on its own, assuming you don't modify it from what works.
-Albatross
Last edited on
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