usleep() problem

[Jozo]

Hi all!!
I want to make loading effect in c++. When I use this code, program works, but I want cout in one line.

#include <iostream>
#include <stdlib.h>
using namespace std;
int main()
{	int i;
	for(i = 0; i < 50; i++)
	{	usleep(100000);
		cout <<"|"<< endl;
	}
	return 0;
}

When I use this code, cout is in one line, but the program doesn't do what I wanted to do. He waits about 50*100000 and then prints 50 times |.

#include <iostream>
#include <stdlib.h>
using namespace std;
int main()
{	int i;
	for(i = 0; i < 50; i++)
	{	usleep(100000);
		cout <<"|";
	}
	return 0;
}

Please help!!!

[R0mai]

Try

#include <iostream>
#include <stdlib.h>
using namespace std;
int main()
{	int i;
	for(i = 0; i < 50; i++)
	{	usleep(100000);
		cout <<"|" << flush;
	}
	return 0;
}

[Jozo]

Oh...
Thank you very much...
Can You tell me what means flush??

[Mythios]

Synchronizes the buffer associated with the stream to its controlled output sequence. This effectively means that all unwritten characters in the buffer are written to its controlled output sequence as soon as possible ("flushed").

http://cplusplus.com/reference/iostream/manipulators/flush/