Stacks&Queues Linked List [Problem with pop and deque]

Alright so it works fine, but the proble is that it pops/deques out all the elements instead of one element. Say for instance I pushed in 5 then 4. The stack would give me 4 and 5 instead of just 4. Vise versa with deque, if I put in 5 then 4. It deques 5 and 4 instead of just 5.

This is my code:

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#include <stdio.h>
#include <malloc.h>
#include <iostream>
#include <Stack>
#include <Queue>
using namespace std;

typedef struct A
{
	int key;
	struct A *stackpop;
	struct A *dequel;
}l;

void push( int );       
void enque( int );       
void dequee( );  
void pop( ); 

char menu()
{
     char vect, Q;
     cout << "\n A) Push " << endl;
     cout << "\n B) Enque " << endl;
     cout << "\n C) Pop " << endl;
     cout << "\n D) Deque " << endl;
     cout << "\n E) Exit " << endl;
     cin>>vect;
     Q=vect;
     return Q; 
}

int main()
{
    int x;            
  	while(1)
	{
        char c; c=menu();
        switch(c)
        {
            case 'a' :
                cout<<"Please enter in #:"<<endl;
		        cin>>x;
                push(x);
                break;

            case 'b' :
                cout<<"Please enter in #:"<<endl;
		        cin>>x;
                enque(x);
                break;

            case 'c' :
                pop();
                break;

            case 'd' :
                dequee();
                break;

            case 'e' :
                exit(0);
                break;
        }
	}
	system("pause");
	return 0;
}

l *head;     
l *tail;     
l *temp1;    
l *temp2;    
l *temp3;    
l *temp4;      

void push( int n )
{
	temp1 = head;
	temp2 = tail;

	if(temp1 == NULL)   
	{
		temp1 = (l *)malloc(sizeof(l));
		temp1 -> key = n;
		temp1 -> stackpop = NULL;
		head = temp1;

		temp2 = (l *)malloc(sizeof(l));
		temp2 -> key = n;
		temp2 -> dequel = NULL;
		tail = temp2;
	}
	else
	{
        temp3 = (l *)malloc(sizeof(l));
        temp3 -> key = n;
        temp3 -> stackpop = head;
        head = temp3;

        while(temp2 -> dequel != NULL)
            temp2 = temp2 -> dequel;

        temp4 = (l *)malloc(sizeof(l));
        temp4 -> key = n;
        temp4 -> dequel = NULL;

        temp2 -> dequel = temp4;
	}
}

void enque(int n)
{
	temp1 = head;
	temp2 = tail;

	if(temp2 == NULL)  
	{
		temp2 = (l *)malloc(sizeof(l));
		temp2 -> key = n;
		temp2 -> dequel = NULL;
		tail = temp2;

		temp1 = (l *)malloc(sizeof(l));
		temp1 -> key = n;
		temp1 -> stackpop = NULL;
		head = temp1;
	}
	else
	{
        temp4 = (l *)malloc(sizeof(l));
        temp4 -> key = n;
        temp4 -> dequel = tail;
        tail = temp4;

        while(temp1 -> stackpop != NULL)
            temp1 = temp1 -> stackpop;

        temp3 = (l *)malloc(sizeof(l));
        temp3 -> key = n;
        temp3 -> stackpop = NULL;

        temp1 -> stackpop = temp3;
	}
}

void pop()
{
    temp1 = head;

    if(temp1 == NULL)       
    {
        cout << "The stack is empty." <<endl;
        return;
    }

    cout << "Popping: " <<endl;
    while(temp1 != NULL)
    {
        printf("\n\t%d",temp1 -> key);
        temp1 = temp1 -> stackpop;
    }
}

void dequee()
{
    temp2 = tail;

    if(temp2 == NULL)       
    {
        cout << "The queue is empty" <<endl;
        return;
    }

    cout << "Dequing: " <<endl;
    while(temp2 != NULL)
    {
        printf("\n\t%d",temp2 -> key);
        temp2 = temp2 -> dequel;
    }
}


How would I make it so it only pops/deques one element and still holds the other numbers in standby if I ask it again?
See lines 158 and 176. What do you see?
Ahhh.. a while loop. Now I feel stupid XD

Thanks!
I think the structure may have memory leaks. I see malloc() but no calls to free().
I didn't really see a difference in it. It didn't seem to have memory leaks, but I'll add it in case. Thanks again ^^
helios was just being nice. Your data structure does have memory leaks.
I know. Sorry if I seemed mean O.o I didn't mean to.
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