problem with aray removal...

[gajji2020]

Hi,,
I have a small problem with my code. I have an array with a list of numbers from o to n.. And n is the calculated value from a formulae.. I placed them in a array and i generate a random number which is present in the array and remove it and place the next number in its place and so on... i am placing the code down here..

int rwall[total];
for(int i=0;i<total;i++)
{
rwall[i]=i;
}

for(int i=0;i<=no;i++)
{
if(i==no)
{
// If the number matches with the nummber in array
// i am going to a label called rem.. There i am moving
the numbers one position forward...
goto rem;
}
rem:
{
for(int j=no;j<wall;j++)
{
rwall[j]=rwall[j+1];
cout<<rwall[j]<<endl;
}
}
}

The "no" is the position in the array to be removed.. Kindly help me with this...

[hamsterman]

What errors are you getting?
What is the value of "wall"?
It should be total-1 or less. Otherwise rwall[j+1] will be out of bounds.
Also, avoid using goto whenever you can.
The structure of your code is not right. Note that rwall[i] == i, so rwall[no] == no. You don't need the for loop. You may want to check if "no" is in range [0; total)...
Lastly, use code tags next time
Good luck

[gajji2020]

Thanks for the reply.. But my basic question is i have an interger array with numbers from 1 to n.... Whenever i get a value called no,i should delete the element in the array at this position(no)... And push the other numbers after this deleted number before by one... Can you write a code snippet for me....?