Why is move ctor called when creating a std::pair?

[JUAN DENT]

Hi,

In the following code:

		const int val = 1;
		auto xx = make_pair(val, A{ val });

the move constructor of A is called. Why? It creates a temporary object which is destroyed afterwards -- seems unnecessary...


Thanks,
Juan

[JUAN DENT]

No, I got it - sorry.

There is actually a temporary object being created in A{val} and this is an rvalue which calls A(A&&)...

Thanks,
Juan