dynamic array

[mike9407]

#include <iostream>
using namespace std;

int main()
{
int *a;
a=new int[10];
a=new int[5];
cout<<&a[10];

delete []a;


return 0;
}
it mean the array size can expand if i create like this?

[Thomas1965]

it mean the array size can expand if i create like this?

No,
arrays are static. Once you create one with size 10 it will stay like this.
If you need a different size you have to create a different array.

a=new int[10];
// Before you create a new array you need to delete the old one first otherwise 
// you will have a  memory leak.
delete []a;
a=new int[5];

cout<<&a[10];

Be careful array index is from 0 to size-1. If you try ro access elements outside this range your program will probably crash.

[mike9407]

it mean the size of the array can't expand?

[MikeyBoy]

it mean the size of the array can't expand?

Correct. You're better off using vectors, if you want a container that can expand to contain more data.