Converting intergers to character

Enter numbers: 0 1 2 3 4 5 6 7 8
output:
A B C

D E F

G H I

how can i convert it using pointers
this is the code:

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#include <iostream>
#include <limits>
using namespace std;
bool encountered[9] = {}; 
int main(){
	int z[3][3];
	char a=0,b=1,c=2,d=3,e=4,f=5,g=6,h=7,i=8,j=9;
	for(int i = 0; i <3; i++)
{
    for (int j=0 ; j<3 ; ++j)
    {
        cout << "Num " << (j+1)+3*i << ": ";
        cin >> z[i][j];
        if(cin.fail()) 
        {
            std::cerr << "Invalid input" << std::endl;
            cin.clear();
            cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
            --j; 
            continue;
        }
        if(z[i][j] > 9 || z[i][j] < 0)
        {
            std::cerr << "Invalid number, should be between 0 and 9" << std::endl;
            --j;
        }
        else if(encountered [z[i][j]-1])
        {
            std::cerr << "You already entered that number" << std::endl;
            --j;
        }
        else 
        {
            encountered[z[i][j]-1] = true; 
        }
    }
}
	 for(char i = 0; i <3; i++)
    {
        for (char j=0 ; j<3 ; ++j)
        {
            cout << z[i][j] << " ";
        }
        cout << endl<<"\n";
    }
    cout<<"Its a magic square";
}
ASCII to dec values.

http://www.asciitable.com/

You'll have to do a bit of simple arithmetic to get the letter you want. But it's just assigning the number 0 to 'A' and adding numbers to your character

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char begin = 'a';
std::cout << (begin+1); // this gets you 'b'; 
I need a pointer one pls help
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#include <iostream>
#include <sstream>
#include <string>
#include <iterator>
#include <algorithm>

int main() {
    std::string line;
    std::cout << "Enter numbers: ";
    std::getline(std::cin, line);
    std::istringstream iss(line);
    std::for_each(std::istream_iterator<int>(iss),
                  std::istream_iterator<int>(),
                  [](int x) { std::cout << static_cast<char>('A' + x) << ' '; });
    return 0;
}
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