How to output occurrence of number in array

I created a menu and one of the options is to output the number of times a number appears in a 12 number array

for example if the numbers in the array

1,2,3,4,3,4,5,6,9,8,6,5
if you entered 3 for example the number outputted is 2

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
  #include "stdafx.h"
using namespace std;

int main()
{
	double big, small, countNumbers;
	double list[12];
	int option;
	double sum = 0;
	big = small = list[0];

	cout << "Enter 12 numbers : ";

	for (int i = 0; i < 12; i++)
	{

		cin >> list[i];

	}

	do
	{

		cout << "\t\tMenu\n";
		cout << "\t0.Display\n";
		cout << "\t1.Total\n";
		cout << "\t2.Average\n";
		cout << "\t3.Largest\n";
		cout << "\t4.Smallest\n";
		cout << "\t99.Exit\n";
		cout << "\t\t Option ? ";
		cin >> option;


		switch (option)
		{
		case 0:

			cout << "Contents\n";


			for (int i = 0; i < 12; i++)
			{
				cout << list[i] << endl;

			}
			break;

		case 1:

			cout << "Total";
			cout << "\n\n";

			for (int i = 0; i < 12; i++)
			{


				sum += list[i];

			}

			cout << sum;

			break;

		case 2:
			
			cout << "average";
			
			for (int i = 0; i < 12; i++)
			{
				sum += list[i];

			}
			
			cout << sum / 12;

			break;

		case 3:

			cout << "Largest";

			for (int i = 0; i < 12; i++)
			{
				if (list[i]>big) 
				{
					big = list[i];
				}
			
			}

		    cout << big;

			break;

		case 4:

			cout << "Smallest";

			for (int i = 0; i < 12; i++)
			{
				if (list[i]<small)
				{
					small = list[i];
				}

			}

			cout << small;

			break;

		case 5:

			cout << "Occurances of value";

			for (int i = 0; i < 12; i++)
			{

			}
			break;
               case 99:
			break;
		
		default:
			cout << "Invalid option\n";
		}while (option != 99);
return 0;
Last edited on
If you're trying to keep track of a number of occurrences of a certain piece of data within a container, create another container to keep track of the repeated variable.

However, what you're asking for in this case would be simpler. Just have a simple int counter, initialize it to 0, and for every time the data item that's asked for appears in the container, increment it.
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