how do I byteswap values?

[hsb910126]

Hello, I have my code here and trying to byte swap the value in before_1~4.
I also have done to make as hex number as well.
All I need to do is swap the before value and come out to be like
before 123456789 to after 987654321.
How do I byteswap this using byteswap function or bitwise operator.
Thank You
Here is my code

#include <iostream>
#include <iomanip>
#include <stdlib.h>
using namespace std;

int main(int argc, char* argv[])
{
	// Display Header
	cout << setw(17) << left << "Byte   Swap   (Hex Version):" << endl;
	cout << setw(17) << left << "Number" << setw(17) << left << "Before" << setw(17) << left << "After" << endl;
	cout << "--------------------------------------------" << endl;

	long Before_1 = 123456789;
	long Before_2 = 728454731;
	long Before_3 = 997499867;
	long Before_4 = 637454579;


	string Number_1 = "1";
	string Number_2 = "2";
	string Number_3 = "3";
	string Number_4 = "4";

	cout << showbase << hex;
	cout << setw(17) << left << "1" << setw(17) << left << Before_1 << endl;
	cout << setw(17) << left << "2" << setw(17) << left << Before_2 << endl;
	cout << setw(17) << left << "3" << setw(17) << left << Before_3 << endl;
	cout << setw(17) << left << "4" << setw(17) << left << Before_4 << endl;

}

[coder777]

That is not 'byte swap'. The easiest way ist to use reverse(...). See example:

http://www.cplusplus.com/reference/algorithm/reverse/?kw=reverse

[Ericool]

a char has 8 bits, so not the same thing. use reverse iterators