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#include <iostream>
#include <fstream>
#include <cmath>
using namespace std;
void A_to_B(const char*); //function for converting ASCII to Binary
void B_to_A(const char*); //function for converting Binary to ASCII
int main(void)
{
cout << " ASCII/Binary Converter" << endl;
cout << " ============================ \n \n" << endl;
char response; //used to store user's response to the next question
char garbage[50]; //used to clear entry buffer in case user types more than 1 character
cout << " 1. ASCII to Binary Converter" << endl;
cout << " 2. Binary to ASCII Converter" << endl;
while(response != '1' && response != '2' && response != 'N' && response != 'n')
//loop if the user's response is none of the above.
{
cout << "\n Enter \"1\" or \"2\" to specify task. Enter \"N\" to quit: ";
cin >> response; //store the user's response in "response"
cin.getline(garbage, 50); //get rid of the entire line from the entry buffer
if(response != '1' && response != '2' && response != 'N' && response != 'n')
//will fun if user enteres unrecognized entry for "response"
cout << " The value you entered was invalid. Please try again" << endl;
}
if(response == 'N' || response == 'n') //if the user chooses to quit
{
cout << "User cancel" << endl;
exit(0);
//output text informing termination, terminate program, return "0" for no error.
}
char text[501];
cout << " Enter the text/code you want to convert: ";
cin >> text;
if(response == '1')
{
A_to_B(text); //if the user chose ASCII --> Binary, to go A_to_B()
}
else //only choice left here is response == 2
{
B_to_A(text); //if the user chose Binary --> ASCII, go to B_to_A()
}
cout << " Conversion finished" << endl;
return 0;
}
void A_to_B(const char* input)
{
int ascii; // used to store the ASCII number of a character
int length = strlen(input); //find the length of the user's input
cout << " ";
for(int x = 0; x < length; x++) //repeat until user's input have all been read
// x < length because the last character is "\0"
{
ascii = input[x]; //store a character in its ASCII number
/* Refer to http://www.wikihow.com/Convert-from-Decimal-to-Binary for conversion method used
* in this program*/
char* binary_reverse = new char [9]; //dynamic memory allocation
char* binary = new char [9];
int y = 0; //counter used for arrays
while(ascii != 1) //continue until ascii == 1
{
if(ascii % 2 == 0) //if ascii is divisible by 2
{
binary_reverse[y] = '0'; //then put a zero
}
else if(ascii % 2 == 1) //if it isnt divisible by 2
{
binary_reverse[y] = '1'; //then put a 1
}
ascii /= 2; //find the quotient of ascii / 2
y++; //add 1 to y for next loop
}
if(ascii == 1) //when ascii is 1, we have to add 1 to the beginning
{
binary_reverse[y] = '1';
y++;
}
if(y < 8) //add zeros to the end of string if not 8 characters (1 byte)
{
for(; y < 8; y++) //add until binary_reverse[7] (8th element)
{
binary_reverse[y] = '0';
}
}
for(int z = 0; z < 8; z++) //our array is reversed. put the numbers in the rigth order (last comes first)
{
binary[z] = binary_reverse[7 - z];
}
cout << binary; //display the 8 digit binary number
delete [] binary_reverse; //free the memory created by dynamic mem. allocation
delete [] binary;
}
cout << endl;
}
void B_to_A(const char* input)
{
int length = strlen(input); //get length of string
int binary[8]; //array used to store 1 byte of binary number (1 character)
int asciiNum = 0; //the ascii number after conversion from binary
char ascii; //the ascii character itself
cout << " ";
int z = 0; //counter used
for(int x = 0; x < length / 8; x++) //reading in bytes. total characters = length / 8
{
for(int a = 0; a < 8; a++) //store info into binary[0] through binary[7]
{
binary[a] = (int) input[z] - 48; //z never resets
z++;
}
int power[8]; //will set powers of 2 in an array
int counter = 7; //power starts at 2^0, ends at 2^7
for(int x = 0; x < 8; x++)
{
power[x] = counter; //power[] = {7, 6, 5, ..... 1, 0}
counter--; //decrement counter each time
}
for(int y = 0; y < 8; y++) //will compute asciiNum
{
double a = binary[y]; //store the element from binary[] as "a"
double b = power[y]; //store the lement from power[] as "b"
asciiNum += a* pow(2, b); //asciiNum = sum of a * 2^power where 0 <= power <= 7, power is int
}
ascii = asciiNum; //assign the asciiNum value to ascii, to change it into an actual character
asciiNum = 0; //reset asciiNum for next loop
cout << ascii; //display the ascii character
}
}
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