Template default argument syntax

[sasauke]

Hello. My problem is quite simple and semantic. So I built a simple class template,
which has one generic type which by default is double.

So I expected to be able to create an object like point p(1, 2);,
instead I am forced to write the ugly point<> p(1, 2);.

My question is: is there a way to fix that somehow while still keeping the same functionality?

#include <iostream>

template<class type = double> //default is double
class point
{
private:
	type x, y;
public:
	point::point(const type &X = 0, const type &Y = 0)
		: x(X), y(Y)
	{}

	type get_x() { return x; }
	type get_y() { return y; }
};

int main()
{
	point<double> p1(1, 2); //OK

	point<> p2(1, 2); //OK

	point p3(1, 2); //error

	std::cin.get();
}

[sasauke]

Well, I managed to fix it with a simple typedef, because unfortunately, that is the C++ syntax.