Pointer function and non-pointer function

[DyslexicChciken]

Given a print function:

void print(int i)
{
    cout << i << endl;
}

Why are we allowed to do this in the main function:

void (*bar)(int);
bar = &print;

But not this:

void fizz(int);
fizz = print;

But when it comes to function parameters, we can pass a pointer to a function or a copy of the function:

void foo(void (*f)(int))
{
    (*f)(1);
}

void test(void f(int))
{
    f(1);
} 

Anyone know the reason for these differences?

[LB]

There is no difference between foo and test:
https://ideone.com/EWDfLF

Functions are not first-class citizens. The weirdness is inherited from C.

[YFGHNG]

Functions are not first-class citizens.

Can you elaborate on that a bit? I haven't heard of that before. Does it mean that functions are inherently (speaking in terms of order of operation) going to be called after pointers to functions?

[LB]

It means that unlike other things (such as integers, strings, etc) functions aren't treated as value types. They have unusual treatment compared to all other parts of the language.