I would to change my operator<<

[Winsu]

I have overloaded the operator<< but what it gets as a argument is a non-const...I think if the function of operator<< is just display the information it should be a const value...i have tried to do it like that but , I dont get it done....any help?? thanks

#include <stdio.h>
#include <iostream>


using namespace std;

class Vector{
	int	   sz;
	double*  elem;		
			
	
	public:
		Vector(const int a):sz{a},elem{new double [a]}{}
			
		Vector(const Vector& a):sz{a.sz},elem{ new double [a.sz]}{
			for(int i = 0;i != a.sz;i++){
			elem[i] = a.elem[i];	
			
			}
		}
		~Vector(){delete [] elem;}
		
		int get_sz () const {
			double temp = sz;
			return temp;
		}
		
		double* get_elem(){
			double* ptr = elem;
			return ptr;
		}			
		
};

	void rellenador(Vector& a){
			double* ptr = a.get_elem();
		for(int i = 0;i != a.get_sz();i++){
			cout<<"Enter value "<<endl;
			int temp;
			cin>>temp;
			ptr[i] = temp;
			
		}
	
	}

	ostream& operator<<(ostream& os,Vector& a){
		double* ptr;
		ptr = a.get_elem ();
		for(int i = 0;i != a.get_sz();i++){
			cout<<*ptr<<endl;
			ptr++;
			
		}
		return os;
	}
	

int main()
{	
	Vector test{3};
	rellenador(test);
	Vector test1{test1};
}

[YFGHNG]

Change your overloaded operator 2nd parameter to const Vector &a

[Winsu]

nope , it discards qualifiers....

[shadowmouse]

You should change the get_elem() function to be const, by declaring it double* get_elem() const

[Winsu]

so , I can pass the value from a const to a non-cosnt??, because I was thinking it was that...

[shadowmouse]

A const function just means that it doesn't modify any of the member functions of the class. It returns a value just like any other function and so ptr can be assigned to the return of get_elem()

[Winsu]

yes, it returns a rvalue, it's what i though but i was getting that mistake and I was getting confused, the error was in other part, thanks!!