C++Noob problem

[9G8MoG1T]

Hey guys I have been at this for a while and I keep running into trouble on verifying if a number is contained within a given string.
Could you guys please kick my butt in the right direction or hint.

#include <iostream>
#include <string>

using namespace std;

int validation(string password)
{
if (password.size() < 7)
{
return 2;
}

char characters;
int valid = 0;
for (int i = 0; i < password.size(); ++i)
{
characters = password[i];
if (toupper(characters) == password[i])
{
valid = 1;
}
}
if (valid == 0)
{
return 3;
}

valid = 0;
///****THIS IS WHERE I AM TRYING TO INPUT A VALIDATION FOR THE NUMBER******

return 1;
}

int main()
{
string password;
while (true)
cout << "Please enter a password: ";
cin >> password;
if (validation(password) == 1)
{
cout << "Thank you, that is a valid passowrd." << endl << endl;
}
else if (validation(password) == 2)
{
cout << "ERROR: Password must be at least 7 characters long. Please, try again." << endl << endl;
}
else if (validation(password) == 3)
{
cout << "ERROR: Password must include at least one uppercase letter. Please, try again." << endl << endl;
}
else if (validation(password) == 4)
{
cout << "ERROR: Password must contain at lease one number. Please, try again." << endl << endl;
}
return 0;
}

[Bdanielz]

Here is how I would try and find a digit in string. Let me know if you have any questions.

#include <iostream>

using namespace std;

int main (){
// get user input
    string user_input;
    cout << "Please enter a password"  << endl;
    cin >> user_input;

// loop over string char by char and keep count of loop
    int str_pos = 0;
    for(char& c : user_input) {

// if a digit do things..
        if(isdigit (c)){

// printing out to prove it works but this might be weird if you have more than one digit
            cout << "There is a digit in your password" << endl;
            cout << "It is located in postion [" << str_pos <<"] of your input" << endl;
        }
        str_pos++;
    }

return 0;
}

[codewalker]

You dont need to run another loop for checking for digit, use same loop where you are checking toupper

modified code

int validation(string password)
{
        if (password.size() < 7)
        {
                return 2;
        }

        char characters;
        int valid = 0;
        for (int i = 0; i < password.size(); ++i)
        {
                characters = password[i];
                if (toupper(characters) == password[i])
                {
                        valid = 1;
                }
                else if(isdigit(password[i]))
                {
                        //Your logic of validation of digit in the string
                }
        }

        if (valid == 0)
        {
                return 3;
        }

        return 1;
}

C++11 style code

int vvalidation(string password)
{
        if (password.size() < 7)
        {
                return 2;
        }

        bool valid = false;
        for (auto c: password)
        {
                if (toupper(c) == c)
                {
                        valid = 1;
                }else if(isdigit(c))
                {
                        //Your logic of validation of digit in the string
                }

        }
        if (valid == 0)
        {
                return 3;
        }

        return 1;
}

You need to add your validation logic in place of the comment

[9G8MoG1T]

THANKS GUYS! You guys were of great help! Life savers!