case switch statment half working need help

[sly858]

was making a somewhat of a Binary to Hex convertor but only 10/15 cases work and the non working are in the middle; 0010, 0011, 0100, 0101, 0110, 0111;;

// Test Code.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include <cmath>
#include <conio.h>
using namespace std;

int main(void)
{	int A;
cout << "Enter the binary starting with the MSB \n";
START:
cin >> A;
switch (A)
{
case 0000:
cout.width(25);
cout << "0\n";
goto START;
case 0001:
cout.width(25);
cout << "1\n";
goto START;
case 0010:
cout.width(25);
cout << "2\n";
goto START;
case 0011:
cout.width(25);
cout << "3\n";
goto START;
case 0100:
cout.width(25);
cout << "4\n";
goto START;
case 0101:
cout.width(25);
cout << "5\n";
goto START;
case 0110:
cout.width(25);
cout << "6\n";
goto START;
case 0111:
cout.width(25);
cout << "7\n";
goto START;
case 1000:
cout.width(25);
cout << "8\n";
goto START;
case 1001:
cout.width(25);
cout << "9\n";
goto START;
case 1010:
cout.width(25);
cout << "a\n";
goto START;
case 1011:
cout.width(25);
cout << "b\n";
goto START;
case 1100:
cout.width(25);
cout << "c\n";
goto START;
case 1101:
cout.width(25);
cout << "d\n";
goto START;
case 1110:
cout.width(25);
cout << "e\n";
goto START;
case 1111:
cout.width(25);
cout << "f\n";
goto START;
}
return 0;
}

[Konstantin2]

Numbers started with zero are octal, not decimal.
10 != 010 = 8

[sly858]

figured it out thanks

[Bdanielz]

I hear using the goto statement is bad...
http://xkcd.com/292/

Why are you using it?

[sly858]

New to programing only way i could get it to repeat the case to solve multiple times; What statement should i be using?

[Konstantin2]

int main(void)
{
int A;
cout << "Enter the binary starting with the MSB \n";
while(true) {
cin >> A;
cout.width(25);
switch (A)
{
case 0:
  cout << "0\n";
  break;
case 1:
  cout << "1\n";
  break;
case 10:
  cout << "2\n";
  break;
...
}
return 0;
}
}