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Counting number of vowels in a sentence

davtk8 (30)
I want to count all the vowels in a string (a, e, i , o, u) and display it as a text-based histogram for example:

[INPUT] The black cat sat up on the orange mat!

[OUTPUT]
A: *****
E: ***
I:
O: **
U: *

The asterisks are supposed to correspond to the number of vowels that are counted (using increments and the function setfill()).

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 #include <iostream>
#include <string>
#include <iomanip>
using namespace std;


void calculateVowels(string text, int a_vowel, int e_vowel, int i_vowel, int o_vowel, int u_vowel)
{

	int a(0), e(0), i(0), o(0), u(0);
	for (int c = 1; c <= text.size(); c++)
	{
		if (text[c] == 'a')
			{a++;}
		else if (text[c] == 'e')
			{e++;}
		else if (text[c] == 'i')
			{i++;}
		else if (text[c] == 'o')
			{o++;}
		else if (text[c] == 'u')
			{u++;}
		
	}
	a_vowel = a, e_vowel = e, i_vowel = i, o_vowel = o, u_vowel = u;
}

int main()
{
	string text;
	cout << "Enter some text:" << endl;
	getline(cin, text);
	int a(0), e(0), i(0), o(0), u(0), non_space_characters;
	calculateVowels(text, a, e, i , o , u);
	cout << text << " " << a << " " << e << " " << i << " " << o << " " << u << endl;
		cout << "A:" << setfill('*') << setw(a) << endl;
		cout << "E:" << setfill('*') << setw(e) << endl;
		cout << "I:" << setfill('*') << setw(i) << endl;
		cout << "O:" << setfill('*') << setw(o) << endl;
		cout << "U:" << setfill('*') << setw(u) << endl;
	system("PAUSE");
		   return 0;
}


This is my output during compilation:

[OUTPUT]
The black cat sat up on the orange mat! 0 0 0 0 0
A:
E:
I:
O:
U:
wildblue (1505)
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