pointer problem?

[zakelong81]

void pointer(int* first , int* second , int* third )

{
	int a, b, c;

        first = &a;
	second = &b;
	third = &c;

	*first = b;
	*second = c;
	*third = a;

	

}

my main

int main()

{

	int first = 1;
	int second = 2;
	int third = 3;

	cout << &first << endl;			//address same

	cout << first << endl;			//a
	cout << second << endl;			//b
	cout << third << endl;			//c

	pointer(&first, &second, &third); //change a b c to b c a (a=b b=c c=a)

	cout << &first << endl;			//address same

	cout << first << endl;			//b
	cout << second << endl;			//c
	cout << third << endl;			//a 

It doesnt seem to work like I want it to work
//change a b c to b c a (a=b b=c c=a)

Why?
1 2 3 should be now 2 3 1

[Zhuge]

You are being passed addresses of variables whose values you want to swap, correct? You are losing those addresses by overwriting them with the addresses of a, b, and c in your function. I don't think that's what you were meaning to do.

[awawsese765]

use this
void pointer( int* first , int * second , int* third )

{
int a, b, c;

a=*first;
b=*second;
c=*third;

*first = b;
*second = c;
*third = a;



}

[Zhuge]

Giving a solution like that is not going to help the TC learn how to program, especially without any explanation. Please don't do this in the future.

[z05DSL3A]

#include <iostream>

void pointer(int * a_ptr, int * b_ptr, int * c_ptr)
{
	// make a copy of the value that a_ptr points to
	int temp = *a_ptr;

	// assign the value that b_ptr points to to the location
	// that a_ptr points to
	*a_ptr = *b_ptr;

	// assign the value that c_ptr points to to the location
	// that b_ptr points to
	*b_ptr = *c_ptr;

	// finally, asign the value stored in temp to the 
	// location pointed to by c_ptr
	*c_ptr = temp;
}

int main()
{
	int first = 1;
	int second = 2;
	int third = 3;

	std::cout << &first << std::endl;			//address same

	std::cout << first << std::endl;			//a
	std::cout << second << std::endl;			//b
	std::cout << third << std::endl;			//c

	pointer(&first, &second, &third); //change a b c to b c a (a=b b=c c=a)

	std::cout << &first << std::endl;			//address same

	std::cout << first << std::endl;			//b
	std::cout << second << std::endl;			//c
	std::cout << third << std::endl;
	return 0;
}

[zakelong81]

@awawsese765 Thanks man that is what i need
I knew my logic was wrong but my idea is right

[zakelong81]

@Grey Wolf this even better thanks man