WAP using ternary operator

[hideepg]

1.WAP in C++ to enter marks in 3 subject and calculate percentage and grade.cond given below (Using Ternary operator)
Per Grade
90-100 A
80-90 B
70-80 C
0-70 D

2. WAP to enter 3 no.s in and print them in ascending and descending order .(Using Ternary operator)

It would be great to know answers ASAP.

[kbw]

What is WAP?

[wildblue]

write a program? and sounds like this is homework or a test?

[Computergeek01]

WAP = "Write A Program"

No thanks OP, we've already gone through the basics ourselves. If you have some code you want help with then we will gladly take a look. Otherwise if you want someone to write it for you then you're looking for the Jobs section.

[hideepg]

yes, WAP means "Write a Program"

//1st program
#include<iostream.h>
void main()
{
int m1,m2,m3,p;
cin>>m1>>m2>>m3; //m1,m2,m3 are marks p is %age
p=(m1+m2+m3)/3;
(p>90)?((cout<<'A'):((P>80)?(cout<<'B'):(P>70)?(cout<<'C')):cout<<'D';
}

The line with bold is the one i am facing problem with.

[wildblue]

main should return int, not void.

The compiler is probably complaining about the parenthesis. There are 8 opening ( but only 7 closing ).

Also you've defined the variable p as lowercase, but you're using an uppercase P in that line.

[Chervil]

That line can be written with just a single cout and single set of parentheses if written like this:

    cout << ( put the required code here );

[kbw]

It helps if you order your multiple ternary operators. Rewriting what you've posted (and moving cout out)

cout <<
    (p > 90) ? 'A' :
    (P > 80) ? 'B' :
    (P > 70) ? 'C' : 'D';

This way, you can visually verify what you've written.

I have transcribed the code as is, so you have an upper and lower case p.

EDIT: I should point out that your checks aren't quite right. For example, what grade does it print for score 90, and what should it print?

[giblit]

As mentioned by kbw you are not doing what you are required.

90-100 A
80-90 B
70-80 C
0-70 D

You say if p > 90 to output 'A' but you need it to be greater than or equal to 90 so either >= 90 or > 89 you will also have to do this with the other cases.