Data validation for vowels and consonants

Hey folks-

I'm trying to make a function that verifies if the char entered is consonant, if not, prompts user to enter another char and when it meets the criteria, return the char. I was able to do this using switch statements (which works, and i'll paste it below) but I wanted to know if there was an easier, perhaps more elegant solution for accomplishing this goal. Thanks for any help.

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char isCons ()  // data validation for consonants
{
char userCons;
bool notCons = false;
cout << "Please enter a consonant: ";
cin >> userCons;
    while (!notCons) {
        switch(userCons) {
        case 'b' : userCons = 'b';
        notCons = true;
            break;
        case 'c' : userCons = 'c';
        notCons = true;
            break;
        case 'd' : userCons = 'd';
        notCons = true;
            break;
        case 'f' : userCons = 'f';
        notCons = true;
            break;
        case 'g' : userCons = 'g';
        notCons = true;
            break;
        case 'h' : userCons = 'h';
        notCons = true;
            break;
        case 'j' : userCons = 'j';
        notCons = true;
            break;
        case 'k' : userCons = 'k';
        notCons = true;
            break;
        case 'l' : userCons = 'l';
        notCons = true;
            break;
        case 'm' : userCons = 'm';
        notCons = true;
            break;
        case 'n' : userCons = 'n';
        notCons = true;
            break;
        case 'p' : userCons = 'p';
        notCons = true;
            break;
        case 'q' : userCons = 'q';
        notCons = true;
            break;
        case 'r' : userCons = 'r';
        notCons = true;
            break;
        case 's' : userCons = 's';
        notCons = true;
            break;
        case 't' : userCons = 't';
        notCons = true;
            break;
        case 'v' : userCons = 'v';
        notCons = true;
            break;
        case 'w' : userCons = 'w';
        notCons = true;
            break;
        case 'x' : userCons = 'x';
        notCons = true;
            break;
        case 'y' : userCons = 'y';
        notCons = true;
            break;
        case 'z' : userCons = 'z';
        notCons = true;
            break;
        case 'B' : userCons = 'B';
        notCons = true;
            break;
        case 'C' : userCons = 'C';
        notCons = true;
            break;
        case 'D' : userCons = 'D';
        notCons = true;
            break;
        case 'F' : userCons = 'F';
        notCons = true;
            break;
        case 'G' : userCons = 'G';
        notCons = true;
            break;
        case 'H' : userCons = 'H';
        notCons = true;
            break;
        case 'J' : userCons = 'J';
        notCons = true;
            break;
        case 'K' : userCons = 'K';
        notCons = true;
            break;
        case 'L' : userCons = 'L';
        notCons = true;
            break;
        case 'M' : userCons = 'M';
        notCons = true;
            break;
        case 'N' : userCons = 'N';
        notCons = true;
            break;
        case 'P' : userCons = 'P';
        notCons = true;
            break;
        case 'Q' : userCons = 'Q';
        notCons = true;
            break;
        case 'R' : userCons = 'R';
        notCons = true;
            break;
        case 'S' : userCons = 'S';
        notCons = true;
            break;
        case 'T' : userCons = 'T';
        notCons = true;
            break;
        case 'V' : userCons = 'V';
        notCons = true;
            break;
        case 'W' : userCons = 'W';
        notCons = true;
            break;
        case 'X' : userCons = 'X';
        notCons = true;
            break;
        case 'Y' : userCons = 'Y';
        notCons = true;
            break;
        case 'Z' : userCons = 'Z';
        notCons = true;
            break;


        default : cout << "Invalid data.  Please enter a consanant: ";
            cin >> userCons;
        }
    }
    return userCons;
}
Untested, but I think this is right:
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const std::string Vowels = "aeiou"; // Screw the 'y'
bool isConsonant = (Vowels.find(std::tolower(userCons)) == std::string::npos);
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