Char Array Size Problem

[LunarB]

So I'm trying to make a program, Which has nothing to do with the topic.
But I ran into a problem.

I need to get a char array size of 6 doing:
char myChar[6];

but the size (6) is undefined until user input.

So I need to do char myChar[var]; (Var being 6 for now).

When I do:

char myChar[6];
Yay! It works!!!

But when I do:

int val = 6;
char myChar[val];

It doesn't work.

Why is this and how can I fix it???

Thanks! -Luna

[Yanson]

if you want to create the array at runtime then you need a dynamic array.

char *myChar = new char[val];

[y510]

#include <iostream>
using namespace std;
#define var 6 

should work fine

[Chervil]

in C++ you have lots of options. A std::vector is perhaps easiest and safest to use. A std::string is also possible here. Once allocated, the syntax for accessing elements is the same for each.

#include <iostream>
#include <vector>
#include <string>

int main()
{
    int var;
    std::cout << "enter array size: ";
    std::cin >> var;
    
    char * myChar = new char[var];  // dynamic character array of length var
    std::string myString(var, ' '); // string of length var, filled with spaces
    std::vector<char> myVec(var);   // vector of length var
    
    myChar[0] = myString[0] = myVec[0] = 'A'; // put something in first element
    
    std::cout << myChar[0]   << std::endl;
    std::cout << myString[0] << std::endl;
    std::cout << myVec[0]    << std::endl;
    
    delete [] myChar; // release memory which was allocated with new []
    
    return 0;
}