What about this function:
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int any(char *s1, char *s2)
{
char array[256];
int i;
if (s1 == NULL) {
if (s2 == NULL) {
return(0);
} else {
return(-1);
}
}
for(i = 0; i < 256; i++) {
array[i] = 0;
}
while(*s2 != '\0') {
array[*s2] = 1;
s2++;
}
i = 0;
while(s1[i] != '\0') {
if (array[s1[i]] == 1) {
return(i);
}
i++;
}
return(-1);
}
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makes it perform better than this function:
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int any(char s1[], char s2[])
{
int i;
int j;
int pos;
pos = -1;
for(i = 0; pos == -1 && s1[i] != '\0'; i++)
{
for(j = 0; pos == -1 && s2[j] != '\0'; j++)
{
if(s2[j] == s1[i])
{
pos = i;
}
}
}
return pos;
}
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?
Last edited on
How well each perform will depend on the strings passed in.
The first one has 3 loops:
- length 256
- length M (length of s1 string)
- length N (length of s2 string)
Therefore it will have 256+N+M iterations
The second one has 2 nested loops:
- length M
- length N
Since the loops are nested, it will have N*M iterations.
Whether or not 256+N+M performs better than N*M depends on the values of N and M.