how can i cin.ignore() only a selected variable?

[Noob Programmer]

how can i stop a loop if

continue == 'n' || coninue == 'N'

i need to keep my

continue character

but cin.ignore my

Number integer

.

[Yanson]

while (Continue != 'n' && Continue != 'N');

[Shaunythesheep]

You can stop the loop by using any other character other n or N as input

[Noob Programmer]

here is my code.

#include <iostream>

using namespace std;
const int Size = 20;
int main()
{
    
	int T[20];
	int A[20];
	char Continue;
	int i = 0, Digit, k;
	do
	{
        for (i = 0; i < Size; i++)
    {
		A[i]=0;
		T[i]=0;
    }
        
		i = 0;
		cout << "\n\nPlease enter first number --> ";
		Digit = cin.get ();
        
        
		while (Digit != '\n' && i < Size)
		{
			T[i] = Digit - '0';
			++i;
			Digit = cin.get();
		}
		for ( k = Size - 1, --i; i >= 0 ; --i, --k)
		{
			A[k] = T[i];
		}
		cout << endl;
		for (i = 0; i < Size; i++)
		{
            cout << A[i];
		}

                              cin.ignore();
		cout << "\n\nContinue? Y or N    ";
		cin >> Continue;
		
	}
    while ( Continue != 'n' || Continue != 'N');
}

my

cin.ignore()

however, deletes even my Continue character and will continuously loop even when i put in 'N'

[cire]

The ignore should occur after line 43.

The condition on line 46 is not correct. It can never be false.


When Continue is 'n' the condition looks like this:

while ( 'n' != 'n' || 'n' != 'N' ) // which simplifies to:
while (    false   ||    true    )  // which, according to truth tables for logical or, is true 

I'm sure you could do the same substitution for 'N'.