problem with return and calling

[Maissa]

so what i want to do is design a program that will give me the entered grades by order , the thing is .i don't know how and i have to use a struct and a function and pointers
my idea was sort of like this :

#include <iostream>
using namespace std;

struct info{

    char name[20];
    int grade;
    
};
int order(struct info a[]){
    int x;
    x=a->grade;
    for(int i=0;i<15;i++){
        if(x < a->grade){ x = a->grade;}
        
    }
    return x;
    
};

int main(){
    
    struct info student[15];
  
    for(int i=0;i<15;i++){
        cout<<"/nenter the name: ";
        cin>>student[i].name;
        cout<<"/nEnter the grade";
        cin>>student[i].grade;
        
    }
    int *p;
      p=  order(student);
   
  

it's completely wrong and sloppy i know . but i really got stuck on what to do and how

any advice?

[Maissa]

I kinnda fixed most of it the only problem now is in the return and calling of the function

#include <iostream>

using namespace std;



struct things{
    
    
    
    char name[20];
    
    int grade;
    
    
    
};

things order(struct things a[]){
    
    int *x,i,j,k;
    
    x=&a->grade;
    for (i = 0; i < 5; ++i)
    {
        for (j = i + 1; j < 5; ++j)
        {
            if (a[i].grade < a[j].grade)
            {
                k = a[i].grade;
                a[i].grade = a[j].grade;
                a[j].grade = k;
            }
        }
    }
    
    return a;
};



int main(){
    
    
    
    struct things student[5];
    
    
    
    for(int i=0;i<5;i++){
        
        cout<<"enter the name: ";
        
        cin>>student[i].name;
        
        cout<<"Enter the grade";
        
        cin>>student[i].grade;
        
        
        
    }
    struct things *p;
    
  p=  order(student);
    
    cout<<*p<<*(p+1);
    
    
}

[Ceset]

Search "passing arrays as function parameters". You will find your answer.