How to get the exception line from the call point.

[GPN]

The below code throws error in the line number 32 where the function is defined.

But How to find the line where the function is called.
That is I want to throw the error at the line number 43 (as here the function is called).

(Using macros works well. But I dont want to use macros.)

The code is:

#include <iostream>
#include <string>
#include <sstream>
using namespace std;
class myEx {
std:: string _file, _message;
int _line;
public:
myEx(std::string file, int line);
std::string toString();
};
myEx::myEx(string file, int line) {
_file = file;
_line = line;
_message = "Unable to copy. ";
toString();
}
string myEx::toString()
{
ostringstream os;
os << _message <<"Error occurred at " << _file << ":" << _line;
return os.str();
}
template <typename T, int size_x>
static void toCopy(T(&x)[size_x], const T(*y)) {
if(strlen(y) >= size_x) {
throw myEx(__FILE__, __LINE__);
}
strncpy(x, y, size_x);
}

int main()
{
char first[4];
string second = "WELCOME";
try {
toCopy(first, second.c_str());
cout << "Copied Successfully! the " <<first<<endl;
}
catch(myEx &e)
{
cout << e.toString() << endl;
}
return 0;
}

[jsmith]

There isn't really a way without macros.