Padding zeroes on to a binary number

[vasiqshair]

The following piece of code is supposed to output the binary representation of a given integer and it does exactly that. However, if the given integer is 2, then output is 01. Is there a way to make the program output 0001. I am working on a C program that outputs 4-bit gray code. Any help is much appreciated.

#include <stdio.h>
#include <math.h>
 
int main(void) {
	long int n=2;
	while (n) {
    if (n & 1)
        printf("1");
    else
        printf("0");
 
    n >>= 1;
}
printf("\n");
	return 0;
}

[whitenite1]

@vasiqhair

Actually, the binary of 2, is 10, or 0010. You have to turn the results you are getting around.

#include <iostream> // For use of the std::cout
#include <stdio.h>
#include <math.h>
 
int main(void)
{
	long int n=2; // Change to a number from 0 thru 15
	int place=3;// Change to 7 for a 8 bit number, 0 to 255
	int code[4]={0}; // Change 4 to 8, for an 8 bit number
	while (n) {
    if (n & 1)
	     code[place]=1;
	else
        code[place]=0;
 
    n >>= 1;
	place--;
}
	for(place=0;place<4;place++) // Change the 4 to 8, if using an 8 bit number
		std::cout << code[place];
	//Not sure how to use printf{} to print data
	printf("\n");
	return 0;
}

[cire]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

#include <stdio.h> #include <math.h> const unsigned bits = 4; void print_bits(unsigned value) { unsigned mask = 1 << (bits-1); while (mask) { printf("%d", (mask & value) != 0); mask >>= 1; } } int main(void) { for (unsigned i = 0; i < (1 << bits); ++i) { print_bits(i); printf("\n"); } }

0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111