Class Report Problem

mb1980 (3)
I need to write a student grade report using C++ classes, i am a beginner with C++.
Sample Output:





Student# Student Name Mt FL P1 P2 CP CGN CGL

-------------------------------------------------------------------------------------------------



876-54-3210 John Baker 98 92 99 98 80 94.90 A

978-34-2300 Karen Chen 85 75 98 95 99 88.50 B

345-21-0244 Pam Marange 60 65 80 50 70 64.25 D


Total number of students processed = 15

Class average for this course = 86.66


this is what i wrote so far:

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#include <iostream>
#include <fstream>
#include <iomanip>
#include <cstdlib>

using namespace std;

class Report
{
private:
	char id [12];
	char name [20];
	double midterm, final, p1, p2, p3;
	ifstream in_file;

public:
	Report ();
	~Report ();

	void print_heading();
	void read_input();
	int calc_grade();
	char convert_grade(int);
	void display_result(char, int);
	ifstream & get();

};

Report::Report()
{ in_file.open ("C://Documents and Settings//Markus//Desktop//P3_input.DAT");

if (!in_file)
{
	cerr<<"Error:File could not be opened"<<endl;
	cerr<<"Program terminating"<<endl;
	exit(1);
}
}
void Report::read_input()
{ 
	in_file.getline(id, 12);
	in_file.getline(name, 20);
	in_file>>midterm>>f1>>p1>>p2>>cp;
	in_file.get();
};

int Report::calc_grade()

	int course_grade;
	course_grade int=(midterm*0,25+f1*0,25+p1*0,20+p2*0,20+cp*0,10);
	return course_grade;
};


char Report::convert_grade(int_grade)
{
	if (grade>=90&&grade<=100)
		return 'A';
	else if (grade>=80&&grade<90)
		return 'B';
	else if (grade>=70&&grade<80)
		return 'C';
	else if (grade>=60&&grade<70)
		return 'D';
	else if (grade>=50&&grade<60)
		return 'E';
	else if (grade>=40&&grade<=50)
		return 'F';

};

char Report::display_result (char letter, int grade)
{
	cout << setw(5)<< "Student#" << setw(15) << "Student Name" << setw(5) << "MT" << setw(5) << "FL"
	<< setw(5) << "P1" << setw(5) << "P2" << setw(5) << "CP" << setw(5)<< "CGN" << setw (5)<< "CGL"<<endl;
	cout<<"-----------------------------------------------------------------------------------------"<<

	cout<< setw(12)<<id<<setw(20)<<name<<setw(3)<<midterm<<setw(3)<<final<<setw(3)<<p1<<setw(3)<<p2<<
	setw(3)<<course_grade<<setw(3)<<grade<<endl;





};

ifstream&report::get()
{
	return in_file;
}

Report::~Report()
{
	in_file.close();
}

int main()
{
	int grade;
	char letter;
	Report s1;
	s1.print.heading();
	ifstream&read_file=s1.get();
	s1.read_input();
	while (!read_file.eof());
	{
		grade=s1.calc_grade();
		letter=s1.convert_grade(grade);
		s1.display_result (letter, grade);
		s1.read_input();
	}

i am getting the following error messages:
------ Build started: Project: Assignment3, Configuration: Debug Win32 ------
Compiling...
Report.cpp
..\..\..\Report.cpp(43) : error C2065: 'f1' : undeclared identifier
..\..\..\Report.cpp(43) : error C2065: 'cp' : undeclared identifier
..\..\..\Report.cpp(49) : error C2144: syntax error : 'int' should be preceded by ';'
..\..\..\Report.cpp(49) : error C2761: 'int Report::calc_grade(void)' : member function redeclaration not allowed
..\..\..\Report.cpp(50) : error C2144: syntax error : 'int' should be preceded by ';'
..\..\..\Report.cpp(50) : error C4430: missing type specifier - int assumed. Note: C++ does not support default-int
..\..\..\Report.cpp(50) : error C2086: 'int course_grade' : redefinition
..\..\..\Report.cpp(49) : see declaration of 'course_grade'
..\..\..\Report.cpp(50) : error C2513: 'int' : no variable declared before '='
..\..\..\Report.cpp(50) : error C2065: 'midterm' : undeclared identifier
..\..\..\Report.cpp(50) : error C2065: 'f1' : undeclared identifier
..\..\..\Report.cpp(50) : error C2065: 'p1' : undeclared identifier
..\..\..\Report.cpp(50) : error C2065: 'p2' : undeclared identifier
..\..\..\Report.cpp(50) : error C2065: 'cp' : undeclared identifier
..\..\..\Report.cpp(51) : error C2059: syntax error : 'return'
..\..\..\Report.cpp(52) : error C2059: syntax error : '}'
..\..\..\Report.cpp(52) : error C2143: syntax error : missing ';' before '}'
..\..\..\Report.cpp(52) : error C2059: syntax error : '}'
..\..\..\Report.cpp(55) : error C2065: 'int_grade' : undeclared identifier
..\..\..\Report.cpp(56) : error C2448: 'Report::convert_grade' : function-style initializer appears to be a function definition
..\..\..\Report.cpp(73) : error C2556: 'char Report::display_result(char,int)' : overloaded function differs only by return type from 'void Report::display_result(char,int)'
..\..\..\Report.cpp(24) : see declaration of 'Report::display_result'
..\..\..\Report.cpp(73) : error C2371: 'Report::display_result' : redefinition; different basic types
..\..\..\Report.cpp(24) : see declaration of 'Report::display_result'
..\..\..\Report.cpp(87) : error C2653: 'report' : is not a class or namespace name
..\..\..\Report.cpp(89) : error C2065: 'in_file' : undeclared identifier
..\..\..\Report.cpp(102) : error C2039: 'print' : is not a member of 'Report'
..\..\..\Report.cpp(9) : see declaration of 'Report'
..\..\..\Report.cpp(102) : error C2228: left of '.heading' must have class/struct/union
..\..\..\Report.cpp(109) : error C2264: 'Report::display_result' : error in function definition or declaration; function not called
..\..\..\Report.cpp(118) : fatal error C1004: unexpected end-of-file found
Build log was saved at "file://c:\Documents and Settings\Markus\Desktop\Workspacefiles C++\Assignment3\Assignment3\Debug\BuildLog.htm"
Assignment3 - 27 error(s), 0 warning(s)
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========







firedraco (6246)
Um, they are all pretty self-explanatory...Just work on one at a time.
smilodon (155)
based on glancing over your code, you only put ; after } at the end of classes, structs, unions, and maybe one or two other things, that you are not using here. In other places you are missing } or {

For your cout<< formatting things try to keep everything consistent, it looks better and is easier to read, this might require playing around with the numbers in setw( ).


..\..\..\Report.cpp(43) : error C2065: 'f1' : undeclared identifier
this error message indicates that the 'f1' has not been defined as a particular type yet and it is on line 43 of file report.cpp

..\..\..\Report.cpp(55) : error C2065: 'int_grade' : undeclared identifier
..\..\..\Report.cpp(56) : error C2448: 'Report::convert_grade' : function-style initializer appears to be a function definition

this means that you are missing a variable type such as int, char, and so forth.

most of the others are similiar errors to the four i mentioned above.
mb1980 (3)
what about this:
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#include <iostream>
#include <fstream>
#include <iomanip>
#include <cstdlib>

using namespace std;

class Report
{
private:
    char id [12];
    char name [20];
    double midterm, final,f1, p1, p2, p3,cp;
    ifstream in_file;

public:
    Report ();
    ~Report ();

    int print_heading();
    void read_input();
    int calc_grade();
	int course_grade();
    char convert_grade(int);
    void display_result();
    ifstream & get();

};


Report::Report()
	{ in_file.open ("C://Documents and Settings//Markus//Desktop//P3_input.DAT");

		if (!in_file)
			{
				cerr<<"Error:File could not be opened"<<endl;
				cerr<<"Program terminating"<<endl;
		     
			 exit(1);
			}
}
void Report::read_input()
{
    in_file.getline(id, 12);
    in_file.getline(name, 20);
    in_file>>midterm>>f1>>p1>>p2>>cp;
    in_file.get();
} 
int Report::calc_grade()
{
int course_grade;
course_grade = (int)((midterm*0.25)+(f1*0.25)+(p1*0.20)+(p2*0.20)+(cp*0.10));
return course_grade;
} 


char Report::convert_grade(int grade)
{
	int course_grade;
	
    if (course_grade>=90&&grade<=100)
        return 'A';
    else if (course_grade>=80&&grade<90)
        return 'B';
    else if (course_grade>=70&&grade<80)
        return 'C';
    else if (course_grade>=60&&grade<70)
        return 'D';
    else if (course_grade>=50&&grade<60)
        return 'E';
    else if (course_grade>=40&&grade<=50)
        return 'F';

} 

void Report::display_result ()
{
	cout << setw(5)<< "Student#" << setw(15) << "Student Name" << setw(5)
		<< "MT" << setw(5) << "FL"
		<< setw(5) << "P1" << setw(5) << "P2" << setw(5) 
	<< "CP" << setw(5)<< "CGN" << setw (5)<< "CGL"<<endl;
    cout<<"-----------------------------------------------------------------------------------------"<<endl;

       
} 

ifstream&Report::get()
{
    return in_file;
}

Report::~Report()
{
    in_file.close();
}

int main()
{
    int grade;
    char letter;
    Report s1;
    s1.print.heading();
    ifstream&read_file=s1.get();
    s1.read_input();
    while (!read_file.eof());
    {
        grade=s1.calc_grade();
        letter=s1.convert_grade(grade);
        s1.display_result (letter, grade);
        s1.read_input();
	cout<<setw(3)<<letter<<setw(3)<<grade<<endl;
    }
}


error message:
------ Build started: Project: Assignment3, Configuration: Debug Win32 ------
Compiling...
Report.cpp
..\..\..\Report.cpp(103) : error C2039: 'print' : is not a member of 'Report'
..\..\..\Report.cpp(10) : see declaration of 'Report'
..\..\..\Report.cpp(103) : error C2228: left of '.heading' must have class/struct/union
..\..\..\Report.cpp(110) : error C2660: 'Report::display_result' : function does not take 2 arguments
Build log was saved at "file://c:\Documents and Settings\Markus\Desktop\Workspacefiles C++\Assignment3\Assignment3\Debug\BuildLog.htm"
Assignment3 - 3 error(s), 0 warning(s)
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========
smilodon (155)
..\..\..\Report.cpp(103) : error C2039: 'print' : is not a member of 'Report'
..\..\..\Report.cpp(10) : see declaration of 'Report'
..\..\..\Report.cpp(103) : error C2228: left of '.heading' must have class/struct/union

when the compiler the compiler sees a '.' it assumes that you are referencing a member or method of a class/struct/union.

example
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    struct myStruct{
                   int a;
                   int b;
                   int c;
} aStruct;

aStruct.a=4;
aStruct.b=5;
aStruct.c=6;
cout<<aStruct.a<<endl;             //This will output 4;


sometimes people use '_' to separate different words in method or variable name.


..\..\..\Report.cpp(110) : error C2660: 'Report::display_result' : function does not take 2 arguments

when you get an error like this when compiling check your call of the function with the definition to make sure what you are inputing is what you are getting out.
mb1980 (3)
Can u please fix this for me i have been working on this since 6am it is 6.56pm here now, or explain what i need to do i am obviously not a programmer.

I am lost maybe i should just take a long walk.
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