void const f() vs void f() const

Could you please explain the different between:

void const f() {} and void f() const {}.
void const f() is equivilent to const void f(), which means the return type (in this case a void) is const. This is totally meaningless not only because it's a void (there is nothing there that needs a const qualifier), but also because it's a return type (returning something as const doesn't make a whole lot of sense).

void f() const makes the function itself const. This only really has meaning for member functions. Making a member function const means that it cannot call any non-const member functions, nor can it change any member variables. It also means that the function can be called via a const object of the class:

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class A
{
public:
  void Const_No();   // nonconst member function
  void Const_Yes() const; // const member function
};


//-----------

A  obj_nonconst;  // nonconst object
obj_nonconst.Const_No();  // works fine
obj_nonconst.Const_Yes(); // works fine

const A obj_const = A(); // const object
obj_const.Const_Yes(); // works fine (const object can call const function)
obj_const.Const_No();  // ERROR (const object cannot call nonconst function) 
returning something as const doesn't make a whole lot of sense
What about 'const T *'? Granted, it's not the pointer that's const, but still.
That's not what I meant. Returning a pointer which is, itself, const: const T* const is pointless.

Returning pointer/ref to a const is certainly not pointless.

I suppose I should've been more clear about that in my original post =P
Last edited on
I was just messing with you. Haha. :-)
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