Nov 23, 2013 at 8:30am UTC
Hello.
I have a deposit of containers and i must delete the cats container. How i can do that?
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#include <iostream>
#include <string>
#include <vector>
using namespace std;
struct Cat
{
string name;
int age;
};
struct Pencil
{
float sharpness;
float length;
};
struct ListOfThings
{
enum Type
{
CatList,
PencilList
} type;
void *listData;
};
vector<Pencil> pencils;
vector<Cat> cats;
vector<ListOfThings> myThings;
int main()
{
cats.push_back( {"Joey" , 4});
cats.push_back( {"Mitzi" , 6});
cats.push_back( {"Garfield" , 10});
pencils.push_back( {1.0f, 17.6f});
pencils.push_back( {0.6f, 12.1f});
pencils.push_back( {1.6f, 24.6f});
pencils.push_back( {0.2f, 18.0f});
myThings.push_back( {ListOfThings::CatList, &cats});
myThings.push_back( {ListOfThings::PencilList, &pencils});
for (const ListOfThings& list : myThings)
{
if (list.type == ListOfThings::CatList)
{
cout << "Ahh... A list of cats... curious...\n" ;
for (const Cat& cat : *static_cast <vector<Cat>*>(list.listData))
{
cout << cat.name << ", age: " << cat.age << '\n' ;
// here i must delete the cats container from myThinks
}
}
else if (list.type == ListOfThings::PencilList)
{
cout << "Hmm... A bunch of pencils...\n" ;
for (const Pencil& pencil : *static_cast <vector<Pencil>*>(list.listData))
{
cout << "sharpness: " << pencil.sharpness << ", length: " << pencil.length << '\n' ;
}
}
}
}
Last edited on Nov 23, 2013 at 10:49am UTC
Nov 23, 2013 at 10:01am UTC
Yes i know that. But here in for loop must delete a container, no an object in front or end but the all container and then break the loop...
How from myThings erase cats container?
In practice from a deposit of containers, how i can erase a container if i know his name only?
Last edited on Nov 24, 2013 at 6:10pm UTC