conversion fro int to int*-error

[enemy]

Hello!
Please what is wrong here:

int Ave(int array_f[5], int& sm)
{

int k=0;

do
{

int e=1;
for (int i=2;i<sm;i++)
{
   if (sm%i==0)
       {
        e=0;break;
       }
}


if (e==1)
{
array_f[k]=sm; cout<<k<<" "<<sm<<" "<<array_f[k]<<endl;k=k+1;
}


sm=sm+1;
}  

               // do
while(k<5);
return k;


}              //function 

int main()
{
int x=128;
int array_m[5];
cout<<Ave(x);
return 0;
}

Compiler says: invalid conversion for int to int* ???

Many thanks!

[nvrmnd]

int Ave(int array_f[5], int& sm)

the first parameter of this function expects an array to be passed, and an int value as a second argument, so at line 39 that should be :

cout << Ave( array_m, x );

and remove 5 in the array parameter declaration in your Ave () function :

int Ave ( int array_f[], int& sm ){ ... }

[enemy]

Hello!!!
Unbelievable!!!
It works now!

Just a question: i wrote return k; on the end of Ave function, but function actually writes out many other things (what I told by cout).

What is the real meaning of "function is returning k"?

Many thanks!

[nvrmnd]

What is the real meaning of "function is returning k"?

it means the current function is terminated and a value is returned ( in your case the value 5 is returned )
to the caller function, or statement :

cout << Ave( array_m, x ); // the value returned by Ave() is 5, hence 5 is printed 

this would also work :

int var = Ave( array_m, x ); // store the value retuned by Ave to var

cout << var; // now print var ( will print 5 also ) 

http://www.cplusplus.com/doc/tutorial/functions/

[enemy]

Thanks, shadow fiend!!!