Coverting string to number

[wmheric]

Please refer the the post:
http://www.cplusplus.com/forum/articles/6046/

On line 25 it says myStream >> myNumber where myNumber is initialized to 0 in line 17. I know that it evaluates false if the input is not a number, but I have no idea what the code really says.
Thank you.

[S6k9GNh0]

#include <iostream>
#include <string>
#include <sstream>

using namespace std;

int main()
{
      stringstream ss ;
      int bob ;

      ss << "5";
      ss >> bob;

      cout << bob;

      return 0;
}

That code wouldn't compile. here's a live version of the stringstream accepting a string literal (number) and then sending it to an integer. Then cout prints it out to the stream.

[jloundy]

Use This Handy Function:

#include <iostream>
#include <stdlib.h>
#include <string>

using namespace std;

int (get_INT(string str))
{
int intValue;
intValue = atoi(str.c_str());
return(intValue);
}

[jloundy]

Use This Handy Function:

#include <iostream>
#include <stdlib.h>
#include <string>

using namespace std;

int (get_INT(string str))
{
int intValue;
intValue = atoi(str.c_str());
return(intValue);
}

[jsmith]

it says to read an integer from the stream and put it into myNumber.

The expression also tests to ensure that a number was successfully read.

This is made possible by two things:

first, operator>> returns a reference to the stream object;
second, the stream object is boolean comparable, and it is defined to return true if no error has occurred on the stream since the last time the error flag was cleared.