Multiples of 4

[VincentOrfeo]

Hey guys, here is the basis of my program:

float x; //start number
float y; //end number

cout<< "Hello, please enter a whole number that will be the starting number. \n" <<endl;
cin>>x;
cout<< "Please enter a whole number that will be the ending number. \n" <<endl;
cin>>y;

for ( ; x<y; x+=4) //counts in multiples of 4
{
cout<<"\n"<< x << "\n"; //displays the multiples
}

if(x>=y) //ends at the ending variable
{
cout<<y; //need to figure out how to get it to stop before y if y isn't a multiple of 4
}

How would I be able to get the end number to not show if it is not a multiple of 4, but show if it is a multiple of 4?

[ResidentBiscuit]

if((x % 4) == 0) cout << x << " is a multiple of 4\n";

[VincentOrfeo]

This helps greatly, but how would I be able to display the end number if it is a multiple of 4? Where would I need to add cout<<y?

[ResidentBiscuit]

My code shows exactly how to display a number if it is a multiple of 4.

[VincentOrfeo]

It works but doesn't show the end # if it is a multiple of 4

i.e.
14 and 54

shows all the way to 50, but not 54. See what I'm saying?

[ResidentBiscuit]

So, you're wanting to see if the last (ones) digit of a number is a multiple of 4?

[Mats]

Only numbers which end in 4 or 8 *have end numbers which are multiples of 4. You want n = 4 and then to output n and then n + 4 = n (which is 8) and then n = n + 16 (which is 24) and then n = n + 4 (28), n = n + 16 (44) etc...

This is easily accomplished in a while loop.

Edit: *Clarified

[ResidentBiscuit]

Only numbers which end in 4 or 8 are multiples of 4

This is false. 12, multiple of 4, does not end in 4 or 8.

Anyways, OP needs to figure out how to get his question out in a clearer manner. I don't think either of us understand what he's asking.

[Mats]

I meant of course, only numbers which end in 4 or 8 have last digits which are multiples of 4.

But yes, the OP does need to clarify, if their question is not yet answered.

[Duthomhas]

OP's question is pretty straight-forward. He even gave examples.

First, don't use floats -- they'll goof up. Use integers (int or unsigned or something like that).

Second, your basic loop continues while x < y, meaning that it does NOT continue even if x == y. To change the end condition, change the comparison to include equality:

for (; x<=y ; x+=4)
{
  cout << x << "\n";
}

Hope this helps.

[VincentOrfeo]

Yeah, this fixed it Duoas. Thanks!