Print out the integers between 2 and 256 that are integer powers of 2.

[KBlythe]

Using a do-while loop, for loop, or while loop.

This is what I have so far but i don't know what to do after that.

#include <iostream>

using namespace std;

int main()
{
   int num;
   int min = 2;
   int max = 256;
}

Also the results should be printed out with 10 integers per line, right justified in a 5 byte field.

[wwwiii]

num = 0;
while(pow(num, min) <= max){
cout << pow(num, min);
num++;
}