charcter arrays???

[ward]

hello every body

Example: if the entered characters are:s d A U M h t I
The output will be:
The letters are:t h d s

i wrote this code to do the example but it didnt work



# include<iostream>
#include <string>
# include<cctype>
using namespace std;

int main()
{
char arr[10];


for(int i=9;i>1;i--)

{
cin>>arr[i];



if(arr[i]<='a'&& arr[i]>='z')
{

cout<<arr[i];
}
else
cout<<"no small letters found";

}


return 0;


}

[kempofighter]

Your if statement is wrong. It shouldn't be possible for the if to evaluate to true. It is impossible for a single character to be <= 'a' AND >= Z. The loop should print "no small letters found" for every character.

Also, please use code tags and reformat posts in the future. If this example weren't so easy I wouldn't have even bothered to read it.

Use isLower in the <cctype> header. It already does what you need. Pass each value of the array to it and it returns true or false.
http://cplusplus.com/reference/clibrary/cctype/islower/

[helios]

Your if condition will never be true.

[Duthomhas]

Remember, if the arr[i] must be in the range 'a' <= arr[i] <= 'z', then code both those conditions using &&:

if (('a' <= arr[i]) && (arr[i] <= 'z'))
  {
  ...

kempofighter also posted you a link to a standard function which checks this very condtion:

if (islower( arr[i] ))
  {
  ...

Also, remember that you can only declare that there are "no small letters found" once you have finished checking every letter in the string.

Good luck!