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- Overloading new operator
Overloading new operator
Hi,
To overload new operator i came across code like this
void*operator new(size_t s,int i)
{ int*q=(jnt *)malloc(s);
*q=i;
return q;
}
when invoking in main they di like this
int*p=new(25)int;
cout<<*p;
If i have to overloaded + operator.....i invoke it like
a+b then it will be taken as a.operator+(b) if i define it as member function and as operator+(a,b) if defined + operator as a friend function.
but here i think accrding to the definition new operator is defined above it should be invoked like this according to my understanding.
a new b;(like first_operand operator second_operand)
a mentions size to be allocated and b intialises.....but i have no ideas how to convey which data types to be allocated memroy(like chars or ints) in this way.I may b totally wrong.
but how the above statement invoking new works??????????????????? its totally out of my understanding ...i am new to c++ ..please help.
To overload new operator i came across code like this
void*operator new(size_t s,int i)
{ int*q=(jnt *)malloc(s);
*q=i;
return q;
}
when invoking in main they di like this
int*p=new(25)int;
cout<<*p;
If i have to overloaded + operator.....i invoke it like
a+b then it will be taken as a.operator+(b) if i define it as member function and as operator+(a,b) if defined + operator as a friend function.
but here i think accrding to the definition new operator is defined above it should be invoked like this according to my understanding.
a new b;(like first_operand operator second_operand)
a mentions size to be allocated and b intialises.....but i have no ideas how to convey which data types to be allocated memroy(like chars or ints) in this way.I may b totally wrong.
but how the above statement invoking new works??????????????????? its totally out of my understanding ...i am new to c++ ..please help.
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