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rounded to the nearest

codeback99 (57)
let say

10.2
10.345
10.23
------
sum


sum/3 = ave

i want ave looks like nearest round so it has to be 10.3

and !

what if i want to fardest round so result will be 10.258

Chriscpp (368)
i want ave looks like nearest round so it has to be 10.3
cout<<fixed<<setprecision(1)<<ave<<endl;

what if i want to fardest round so result will be 10.258
cout<<fixed<<setprecision(3)<<ave<<endl;
codeback99 (57)
the thing is you dont know which number going to be a input

it could be
10.3423
10.4435453
10.345345
Chriscpp (368)
it can be every number
codeback99 (57)
No, for
10.3423
10.4435453
10.345345

the result should be 10.xxxx
MiiNiPaa (8886)
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#include <iostream>
#include <string>
#include <algorithm>
#include <iomanip>

int main()
{
    std::vector<double> values;
    std::string temp;
    size_t prec = 1000; //Change it later to constant from <limits>
    //input either a filestream orstd::cin or something else
    while(std::getline(/**/input/**/, temp)) {
        prec = std::min(prec, temp.size() - temp.find('.') - 1);
        values.push_back(std::stod(temp));
    }
    double avg = std::accumulate(values.begin(), values.end(), 0.0) / values.size();
    std::cout << std::fixed << std::setprecision(prec) << avg;

//1st
12.45
12.555
^Z
12.50
//2nd
44.2345
0.123
1564.123557
^Z
536.160

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