Binary Representation of a Number

[codedhrj]

Below code is for Binary Representation of a Number.
This code works fine.....but i don't know why
if((x&(0x80000000))>0) should be <0 instead of >0
because if first bit of x is 1, number generated would be -2147483748 which is less than 0 but still this code works....
Please Help

#include<stdio.h>
int main()
{
int x;
scanf("%d",&x);
for(int i=0;i<32;i++)
{
if((x&(0x80000000))>0)
printf("1");
else
printf("0");
x=x<<1;
}
printf("\n");
getchar();
getchar();
return 0;
}

[Smac89]

Was as confused as you were also, so I went ahead and printed the values of x and the value of the & condition. Turns out the value of the condition results in an unsigned value therefore checking for < 0; would not have produced desired results

#include<stdio.h>
int main()
{
	FILE* out = fopen("valueofx.txt", "w+");
   int x;
   scanf("%d",&x);
   for(int i=0;i<32;i++) 
   {
      if((x&(0x80000000))>0)
      	putchar('1');
      else
      	putchar('0'); 
      fprintf(out, "%d %u\n", x, (x&(0x80000000)));
      x=x<<1;
   }
   putchar('\n');
   getchar();
   return 0;
}

Output:

234534 0
469068 0
938136 0
1876272 0
3752544 0
7505088 0
15010176 0
30020352 0
60040704 0
120081408 0
240162816 0
480325632 0
960651264 0
1921302528 0
-452362240 2147483648
-904724480 2147483648
-1809448960 2147483648
676069376 0
1352138752 0
-1590689792 2147483648
1113587712 0
-2067791872 2147483648
159383552 0
318767104 0
637534208 0
1275068416 0
-1744830464 2147483648
805306368 0
1610612736 0
-1073741824 2147483648
-2147483648 2147483648
0 0

And here is the value 234534 converted to binary:
00000000000000111001010000100110

Notice how the 1's match up with the places where 2147483648 appears in the output?