While Conditions

[egg management fee]

I'm trying to work through a program and I got it to work, but I'm wondering if there is a cleaner way to write what I'm trying to do. I need to get 2 numbers, run them through an equation and display the answer. The program needs to do this until one of the numbers are 0. Here is what my while loop looks like:

      while ((cin >> x >> y) && ((x != 0) && (y != 0)))
    {
        cout << hm(x, y);
        cout << " is the answer.\n";
        cout << "Enter the next two numbers (q to quit): ";
    }

This worked exactly like I wanted it to, but I was wondering if there is a cleaner way to write this condition? I just don't want to get into bad habits before I move onto more difficult stuff. I would appreciate any feedback.

[LB]

while ((cin >> x >> y) && ((x != 0) && (y != 0)))
while ((cin >> x >> y) && x && y)

egg management fee wrote:

I just don't want to get into bad habits before I move onto more difficult stuff. I would appreciate any feedback.

Your current way is already a better habit than my suggested 'cleaner' way ;)

[egg management fee]

Thank you very much for your feedback!