Convert String into integer

[aMo38]

Turn String a into integer x. a can be a letter from A to J. I' having trouble just making if statements like this.

string a;
int x;
if (a[0] = 'A')
{
 cout << endl << "It's A" << endl;
  x = 0;	
}
else if (a[0] = 'B')
{
   cout << endl << "It's B" << endl;
   x = 1;
	 }

I thought I could also make a switch statement but string a would need to be an integer.

[Stewbond]

try this:

Your first problem is that you are using
if (a[0] = 'A')]
instead of
if (a[0] == 'A')

Secondly, a massive chain of if, else if statements means that there is certainly a better way to do this.

'A' is the ascii representation for the numeric value 0x41. Try this:

int char2int(char c)
{
    return (int)(c - 0x41);
}

or

int char2int(char c)
{
    return (int)(c - 'A');
}

http://www.asciitable.com/