Can this code be shortened?

[mrronoah]

Hi I am a beginner and I am just wondering if this code can be shortened and how it would be done. Its not an important project or anything I was just messing around.
There is a float for the price of whatever, you enter the amount of money you have and then it will print out what change you would receive. Please note that I am in Australia and we have $1 coins here haha.

#include <iostream>

int main(int argc, const char * argv[])
{
    float price = 96.5;
    float moneyin;
    int hundreds;
    int fifties;
    int twenties;
    int tens;
    int fives;
    int twos;
    int ones;
    int fiftyc;
    int twentyc;
    int tenc;
    int fivec;
    std::cout << "The price is $" << price << std::endl << "Insert cash!\n";
    std::cin >> moneyin;
    if (moneyin < price) {
        std::cout << "Not enough\n";
    }
    else {
        moneyin = moneyin-price;
        hundreds = moneyin / 100;   moneyin = moneyin - hundreds*100;
        fifties = moneyin / 50;     moneyin = moneyin - fifties*50;
        twenties = moneyin / 20;    moneyin = moneyin - twenties*20;
        tens = moneyin / 10;        moneyin = moneyin - tens*10;
        fives = moneyin / 5;        moneyin = moneyin - fives*5;
        twos = moneyin / 2;        moneyin = moneyin - twos*2;
        ones = moneyin / 1;        moneyin = moneyin - ones*1;
        fiftyc = moneyin / 0.5;        moneyin = moneyin - fiftyc*0.5;
        twentyc = moneyin / 0.2;        moneyin = moneyin - twentyc*0.2;
        tenc = moneyin / 0.1;        moneyin = moneyin - tenc*0.1;
        fivec = moneyin / 0.05;        moneyin = moneyin - fivec*0.05;
        std::cout << hundreds << " $100 note/s:" << std::endl;
        std::cout << fifties << " $50 note/s:" << std::endl;
        std::cout << twenties << " $20 note/s:" << std::endl;
        std::cout << tens << " $10 note/s:" << std::endl;
        std::cout << fives << " $5 note/s:" << std::endl;
        std::cout << twos << " $2 coin/s:" << std::endl;
        std::cout << ones << " $1 coin/s:" << std::endl;
        std::cout << fiftyc << " 50c coin/s:" << std::endl;
        std::cout << twentyc << " 20c coin/s:" << std::endl;
        std::cout << tenc << " 10c coin/s:" << std::endl;
        std::cout << fivec << " 5c coin/s:" << std::endl;
    }
    return 0;
}

[fg109]

Here's one method using arrays:

#include <iostream>

int main(int argc, const char * argv[])
{
    float price = 96.5;
    float moneyin;

    const int NUMVALUES = 11;
    float values[] = {100, 50, 20, 10, 5, 2, 1, 0.5, 0.2, 0.1, 0.05};
    float count[NUMVALUES] = {0};

    std::cout << "The price is $" << price << std::endl << "Insert cash!\n";
    std::cin >> moneyin;
    if (moneyin < price)
    {
        std::cout << "Not enough\n";
    }
    else
    {
        float changedue = moneyin - price;
        for (int i = 0; i < NUMVALUES && changedue > 0; i++)
        {
            while (changedue >= values[i])
            {
                changedue -= values[i];
                count[i]++;
            }
            if (count[i] > 0)
            {
                if (values[i] >= 5)
                    std::cout << count[i] << " $" << values[i] << " note(s)" << std::endl;
                else if (values[i] >= 1)
                    std::cout << count[i] << " $" << values[i] << " coin(s)" << std::endl;
                else
                    std::cout << count[i] << " " << values[i] * 100 << "c coin(s)" << std::endl;
            }
        }
    }
    return 0;
}

If you don't have pennies ($0.01 coins), you could wind up paying more than change due.