Trouble understanding Leap year function

[SamuelAdams]

When I run this, the return value is always "1".
I left in my test code
I'm trying to figure out why the return value is always 1 and how to fix it.
Just to make sure I'm correct, I think the return should be "0" if it's leap year correct ?

#include <iostream>
#include <cmath>
using namespace std;

bool isALeapYear( int year )
{
// Test code	
	cout << year << " ";
	cout << year %4 << " ";
	cout << year %100 << " ";
	cout << year %400 << " " << endl;
// Test code
	if (year %4==0)
	{cout << year << " " << "leap year" << endl;}

/* Check if the year is divisible by 4 or is divisible by 400 */
	return ((year % 4 == 0 && year % 100 != 0) || ( year % 400 == 0));
}


int main()
{
	for (int i=1992; i < 1997; i++)
	{
	isALeapYear (i);
	 cout << i << " " << "Return: " << isALeapYear << endl;
	}
	return 0;
}

PS. this is for personal learning, not school work, although I got the idea from some school projects I have seen on here.

[LB]

for (int i=1992; i < 1997; i++)
	{
		isALeapYear (i);
		cout << i << " " << "Return: " << isALeapYear(i) << endl;
	}

[ResidentBiscuit]

cout << i << " " << isALeapYear(i) << endl;

[vlad from moscow]

Function name in expressions is converted implicitly to the bool type

cout << i << " " << "Return: " << isALeapYear << endl;

So you will always get output

Return: 1

You should write

cout << i << " " << "Return: " << isALeapYear( i ) << endl;