C++ Program to find string length

[pavithrak2006]

I wrote below program to find lenght of string...It works in the case only when i enter a string continous without any spaces between words example: Itiswonderful

I was thinking of such a logic where it can count the lenght when spaces are also there for E.g.

Program should be able to give output to this string with spaces "It is wonderful".

Please could you help me with this?

#include<iostream>
#include<conio.h>
#include<string>

using namespace std;

main()
{
int length;
char str1[30];
cout<<"Please enter string for which you want to find length"<<endl;
cin>>str1;
length=strlen(str1);
cout<<"Length of string entered"<<length<<endl;
system("PAUSE");
}

[nickul]

Try this:

#include<string>
#include<iostream>

using namespace std;

main()
{
string str1;
cout<<"Please enter string for which you want to find length"<<endl;
cin>>str1;
length=str1.size();
cout<<"Length of string entered"<<length<<endl;
system("PAUSE");
}

[vlad from moscow]

When you use operator >> it reads until a white space will be encountered. To read a sentence with blanks you should use function std::getline instead of operator >>

For example

char s[30];

std::cin.getline( s, sizeof( s ) );

std::cout << s << std::endl;

By the way you shall write

int main()

instead of

main()

Also you should include header <cstring> instead of <string>. And variable length shall be declared as size_t length; instead of int length;

[pavithrak2006]

I modified to the below code as menioned above and for e.g. if i type

good night ...output comes as night. Could you please help me?

#include<iostream>
#include<conio.h>
#include<cstring>

int main() {
size_t length;
char str1[100],s[30];
cout<<"Please enter string for which you want to find length"<<endl;
cin>>str1;
std::cin.getline( s, sizeof( s ) );
std::cout << s << std::endl;
system("PAUSE");
}

[pavithrak2006]

I also tried solution by Nickul and get an error "15 J:\C++ Programs\StrLength.cpp request for member `size' in `str1', which is of non-class type `char[100]' "

How to proceed. Please could you help?

[vlad from moscow]

Remove from this code snip

char str1[100],s[30];
cout<<"Please enter string for which you want to find length"<<endl;
cin>>str1;
std::cin.getline( s, sizeof( s ) );

declaration of str1, and statement cin>>str1;

[nickul]

"I also tried solution by Nickul and get an error "15 J:\C++ Programs\StrLength.cpp request for member `size' in `str1', which is of non-class type `char[100]' ""

You have to declare str1 as string for the .size() to work, as I mentioned in my first reply... you probably missed that

But, as vlad mentioned, you have to use cin.getline(str1, maximum size of s(enter a number here)) instead of cin, otherwise it won't read past the space.

So, it would be like this(without using the string class, as it does not work with cin.getline):

#include<string>
#include<iostream>

using namespace std;

int main()
{
char str1[100];
cout<<"Please enter string for which you want to find length"<<endl;
cin.getline(str1,100);
length=strlen(str1);
cout<<"Length of string entered"<<length<<endl;
system("PAUSE");
return 0;
}

[moorecm]

string line;
getline( cin, line );
cout << line.size() << endl;