Problem with NOT using an array

[Cdawg]

I'm not allowed to use an array for this code but I can't figure out how not to.
I need the following code to work unlimited times until 999 is entered then output the information

void process_fees(double cost)
{
	int count;
        double car[20];
	double total=0;
	cout << "Please enter the hours" << endl;
	for (int i=0; i<20; i++)//I need this to be done unlimited times
	{
	    car[i] = (process_fee() * 3.00);//I need "car" to be saved and output it later
	}
}

double process_fee()
{
	int hours;
	cin >> hours;
	if (hours == 999);
	else 
	     return hours;
}

[S6k9GNh0]

Your post doesn't make much sense. You said you aren't allowed to use an array but I don't see an array in your current code. What's the problem?

[mcleano]

To do an infinite for loop the code is: for(;;) adn then you can call your function.

Personally though, I would use a do while loop and not use a function call.
Also line 17 doesn't mean anything, there are no statements if the conidiotn is true. I think what you want is if(hours != 999) return hours; #

You don't need to use an array with numbers, using int will be fine.

EDIT*****
Not sure how i missed that before, was doing things at speed! You aren't using any arrays. The statement on line 4 is invalid. I think you need to look over your code again, or maybe restart for ease and really think about how your program is going to run, line by line.

[Gumbercules]

What exactly are you expected to do? If you need the user to input numbers and after inputting 999 return each value * 3 in reverse order, you could use recursion.