Bhaskara with class

[will094]

Hey people, sup?
So, this is my very first topic here, and I have a question. Here follows my code and the output it generates:

#include "iostream"
#include "math.h"
using namespace std;

class Bhaskara {
    float *x, *y, *z;
  public:
    Bhaskara (float, float, float);
    ~Bhaskara ();
    float delta() { return (pow(*y, 2) - 4 * *x * *z); }
    float x1() { return ((- *y + sqrt(delta())) / 2 * *x); }
    float x2() { return ((- *y - sqrt(delta())) / 2 * *x); }
};

Bhaskara::Bhaskara (float a, float b, float c) {
    x = new float;
    y = new float;
    z = new float;
    *x = a;
    *y = b;
    *z = c;
}

Bhaskara::~Bhaskara () {
    delete x;
    delete y;
    delete z;
}

int main() {
    float i, j, v;
    cout << "Write the value of a: ";
    cin >> i;
    cout << "Write the value of b: ";
    cin >> j;
    cout << "Write the value of c: ";
    cin >> v;
    Bhaskara bha(i, j, v);
    if (bha.delta() < 0) {
         cout << "The roots don't exist in the set of Real numbers." << endl;
    } else if (bha.delta() == 0) {
         cout << "The roots are equal:\nx1 = " << bha.x1() << "\nx2 = " << bha.x2() << endl;
    } else {
         cout << "The roots are different:\nx1 = " << bha.x1() << "\nx2 = " << bha.x2() << endl;
    }
    return 0;
}

Write the value of a: 2
Write the value of b: 5
Write the value of c: -3
The roots are different:
x1 = 2
x2 = -12
Press any key to continue...

My question is: why this code returns the value without dividing the result of (- *y + sqrt(delta())) / 2 * *a) or (- *y - sqrt(delta())) / 2 * *a)?
I know it's actually more a calculation question than a code one, but I need some help.

[MiiNiPaa]

I will show you how your code actually computes due to operator precedence (I omit the dereference operator):
-y ± ( (sqrt(delta)/2) * x )
It's the same as question "what is 2+2*2"

Use parenteses to force needed order of operations.

[ne555]

a/b*c is associated as (a/b)*c not as a/(b*c)

x = new float; please cut your left hand.