Problem with argv[]

[krutuk]

I write in Linux in gedit, then execute program in terminal.
I have a problem with that program. Here is a code:

#include <iostream>
#include <cstdio>

using namespace std;

int main(int argc, char* argv[])
{
    FILE *fp;
    char ch;
    
    if(argc!=2)
    {
        cout<<"You should enter a filename"<<endl;
        return 1;
    }
    if((fp=fopen(argv[1],"w"))==NULL)
    {
        cout<<"Can't open the file"<<endl;
        return 1;
    }
    do
    {
        ch=getchar();
        putc(ch,fp);
    }while(ch!="."); //mistake here but I don't know the way to correct it
    fclose(fp);

    return 0;
}

Compiler gives a mistake:
error: ISO C++ forbids comparison between pointer and integer

[MiiNiPaa]

change }while(ch!="."); to }while(ch!='.');
You are trying to compare char with string literal.

[binarybob350]

You want char '.' not string "."

change

}while(ch!=".");

to

}while(ch!='.');

[krutuk]

Thanks guys. I have done so stupid mistake.