It is a definition of an array and initialization of it with values in braces.
sizeof( int ) is the size in bytes of an object of type int.
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So basically
n = 6/ 32767?
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no. Sizeof returns the size in bytes.
So assuming an int is 4 bytes:
sizeof(A) == 24 (array of 6 ints, each 4 bytes)
sizeof(int) == 4 (size of a single int)
sizeof(A) / sizeof(int) == 6 (the number of elements in the array).
Though this is a poor way to determine the array size because it is error prone (it will not work as expected if 'A' is a pointer).
n = sizeof(A)/sizeof(int);
This will give you the total elements in the array.
sizeof( A )
- Total elements of( typically ) 4 bytes.
sizeof(int);
- Again, typically 4 bytes for an int.
I say 'typically' because it can vary from computer to computer.
So, 5 elements of type int would be 5 * 4 = 20 bytes.
So the above code:
n = elements * 4 bytes / type int( 4 bytes ) = total elements in the array.
Hope you understand that. (:
Faster at typing, Disch? lol.
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Please open at last some book on C++ and read it. It is not a forum for those who is even lazy to open a book.