Answer as soon as possibe please; Linked list: I've a small question

[Rehan FASTian]

If the prototype of my function is void sell_item(store **head,store **tail). In main i've passed sell_item(&head,&tail), where head & tail where both pointers of store(struct) type.

Now I want to access the the content where head is pointing to. How shall I access it? Like *head->next??? But this is not working.
where next is another member of store storing pointing to the next location of memory (pointing to next node).

[LB]

Your function logically does not make sense. Sell what item? To who? How?

[georgewashere]

The question you should be asking is why is the prototype of your function accepting a pointer to a pointer to a struct or type store?

If head and tails are pointers to store ( aka Store * head, *tail ) don't you think your prototype should reflect that?
void sell_item(store * head, store * tail) ?

That way you could access the information in head & tail like so..

head->member1 = 30;
tail->member1 = 31;

[LB]

Currently, you'd have to use (*head)->next

[D80DSL3A]

@georgewashere Passing a pointer by copy won't allow the pointers to be reassigned if the 1st(head) or last(tail) node are deleted.

The pointers must be passed either by reference, or by passing a pointer to each pointer. I prefer pass by reference because it simplifies the syntax of their usage in the function.
Pass by reference:

void sell_item(store*& head, store*& tail)// hey!! How do we know what to sell here (LB's point)?
{
    head = head->next;// 1st node deleted. head reassigned
}

Pass a pointer:

void sell_item(store** head, store** tail)
{
    *head =(*head)->next;// per LB
}

EDIT: Brain-fart correction